Question

2. A 60 W filament lamp is powered by the 240 V mains electricity supply.

Answer 1

Answer:

I(current)=0.25A

R (resistance)=960ohms

Explanation:

1.)

P=60W

V=240V

I=?

Power= Current× Potential difference

P=IV

substitute 60 for P and 240 for V

60=I×240

I=60÷240

I=0.25A

Therefore, I=0.25A

2.) V=IR

Substitute 240 for V and 0.25 for I

240=0.25×R

R=240÷0.25

R=960W

Therefore, R=960W