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lyudmila [28]
3 years ago
10

a circular mirror is surrounded by a square metal frame. the radius of the mirror is 5x. the side length of the metal frame is 1

5x what is he area of the metal frame?
Mathematics
1 answer:
Eva8 [605]3 years ago
3 0
Since the side of the square frame is 15x, the area of the frame in whole would be:

(15x)² = 225x²

Now if we subtract out the circle mirror with a radius of 5x, we get:

225x² - πr²
225x² - π(5x)²
225x² - π25x²

We can factor out a 25x² and get:

25x² (9 - π)
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1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
I NEED HELP! PLEASE HELP ME I WILL GIVE YOU 5 STARS AND A HEART! PLEASEEEEE.THANK YOU,
DerKrebs [107]
I believe #1 is a prism and #2 is a cylinder. <span />
6 0
3 years ago
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Need help filling in the blanks: selling price using markup.
Xelga [282]

Answer:

Refer to the explanation.

Step-by-step explanation:

Let's take each one at a time.

1.

To solve for the complement, we simply subtract our markup rate by 100%.

100% - 30% = 70%

Now to solve for the selling price, we use the formula

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{86.74}{0.70}

Selling Price = $123.91

2.

We do the same process with the first number.

100% - 40% = 60%

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{220.00}{0.60}

SellingPrice = $366.67

3.

The same as the first two.

100% - 20% = 80%

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

SellingPrice=\dfrac{89.50}{0.80}

SellingPrice = $111.88

4.

Now to solve for the markup rate, we use the formula:

MarkupRate=\dfrac{Markup}{SelingPrice}

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.

Selling Price = $235.28

Cost = $199.99

Markup = $235.28 - $199.99

Markup = $35.29

Now the we know our markup, we can then solve for the markup rate using the formula.

MarkupRate=\dfrac{Markup}{SelingPrice}

MarkupRate=\dfrac{35.29}{235.28}

MarkupRate = 0.1499 x 100 = 14.99% or 15%

5.

Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

SellingPrice=\dfrac{Cost}{ComplementOfMarkupRate}

Selling Price = $30.77

Complement = 65% or 0.65

This will then give us.

30.77=\dfrac{Cost}{0.65}

We multiple both sides of the equation by 0.65 to leave our cost alone.

30.77 x 0.65 = Cost

Cost = $20

4 0
3 years ago
Best explained and correct answer gets brainliest!!
sp2606 [1]
The correct answer is c
7 0
3 years ago
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What is the area, in square centimeters, of the figure below? question 2 of 10
boyakko [2]

Answer:

area = 1/2× base×height

<u>1</u>×5.8×2.4

2

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2

=6.96cm²

7 0
3 years ago
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