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3 years ago

Bonsoir, je n'arrive pas à comprendre cette exercice et j'aurai besoin d'aide. Merci d'avance

Mathematics

1 answer:

jenyasd209 [6]3 years ago

6 0

Answer:

Step-by-step explanation:

Vous devrez mettre chaque nombre au carré et après, vous devrez les multiplier ensemble et une fois que vous aurez fait cela, vous devrez simplifier. Si cela aide, puis-je avoir le plus de courage. Merci.

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Find the geometric sum: 40 + 20 + 10 + … + 0.078125

sveticcg [70]

$S=40+20+10+\cdots+0.078125$
$S=40\left(1+\dfrac12+\dfrac14+\cdots+\dfrac1{512}\right)$
$S=40\left(1+2^{-1}+2^{-2}+\cdots+2^{-9}\right)$

$2^{-1}S=40\left(2^{-1}+2^{-2}+2^{-3}+\cdots+2^{-10}\right)$

$\implies S-2^{-1}S=40\left(1-2^{-10}\right)$
$\implies\dfrac12S=40\left(1-\dfrac1{1024}\right)$
$\implies S=80\left(1-\dfrac1{1024}\right)=\dfrac{5115}{64}=79.921875$

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3 years ago

Which table contains only points that lie on the line of the equation y = 6x - 6?

Fittoniya [83]

Answer:

The answer is G

Step-by-step explanation:

2 x 6 = 12

12 - 6 = 6

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-2 x 6 = -12

-12 - 6 = (-18)

7 0

3 years ago

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What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$

$x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}$

$x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925$

$Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925$

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

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4 years ago

Draw a square with a perimeter of 16 feet

Colt1911 [192]

You need a ruler and a pencil. Oh and paper. Make sure that each side is equal to 4 inches. Then make a scale of 1:12, meaning 1 inch=1 foot.

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3 years ago

How do u graph x>-6 on a line graph?

erastova [34]

Ok so if -6 is the y intercept you look for -6 on the y axis and use rise over run up one over one until you can't plot anymore and then down one over one and do the same thing did that help you Phil?

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3 years ago

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