Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
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If it’s not message me I’ll give u the answer
Answer: x=34
Step-by-step explanation:
1. You subtract 2x from 5x on the other side to get rid of the 2x leaving you with 3x.
2. Then you add 5 to 97 to get rid of the -5, giving you 102 on the opposite side.
3. divide 102 by 3x giving you 34.
5x-5=2x+97
-2x -2x
3x-5=97 <u><em>X=102</em></u>
+5 +5
3x=102
x/3 102/3
The solution of the given equation is (3,6). The correct option is B.(3,6)
<h3>Given equations,</h3>
<h3>How to solve the equations?</h3>
putting the value of y from equation (1) in equation (2) , we get
substitute the value of x=3 in equation (1) we get,
Hence, the solution of given equation is (3,6).
So, the correct option is B.
For more details about the system of equations, follow the link:
brainly.com/question/12895249
