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tangare [24]
3 years ago
10

Gabriellas school is selling tickets to a fall musical. On the dirst day of ticket sales the school sold 10 senior citizen ticke

ts and 14 student tickets for a total of $212. Tje school took in$232 on the second day by selling 12 senior citizen tickets and 14 student tickets. What is the price each of one senior citizen tickets and one student ticket?
Mathematics
1 answer:
Tanya [424]3 years ago
6 0
A senior ticket costs $10, while a student ticket costs $8. You can solve this system of equations by the elimination method.

We can use x as the variable for the senior tickets, and y as the variable for the student tickets and represent it with these equations:
10x+12y=212 and 12x+14y=232

Next, multiply each entire equation by a variable so they can eliminate each other. I used 12 and -10 here so it would be 120x-120x to eliminate that variable.
12(10x+14y=212) and -10(12x+14y=232)

Our new equations are:
(120x +168y= 2544) and (-120x-140y=-2320)

You can then subtract one of the equations from the other leaving you with 28y=224 and solve it for y to get 8.
So the price of a student ticket is 8.

Pick any of the original equations and by replacing y with 8, you can solve to find x. (X is the variable we assigned for senior tickets)
10x+14(8)=212
10x+112=212
10x=212-112
10x= 100
1x=10
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3 years ago
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
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Answer:

(a) 0.999664

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Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

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Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

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So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

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Answer:

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