Surface area of pyramids

1 answer:

6 0

Multiply the side length of the base by the slant height and divide by two. Then, multiply by 4. This will give you the lateral surface area of the pyramid. Add the base surface area and the lateral surface area. Hope this helps you out

You might be interested in

A pair of equations is shown below:

lesya692 [45]

Answer:

The solution to the pair of equations is $x=1,y=2$

Step-by-step explanation:

The given equations are:

$y=6x-4$

$y=5x-3$

To solve the pair of equations graphically, we need to graph the two equations. Their point of intersection is the solution to the pair of equations.

The functions are in the form;

$y=mx+b$

where m=6 is the slope and b=-4 is the y-intercept of $y=6x-4$ .

and where m=5 is the slope and b=-3 is the y-intercept of $y=5x-3$ .

The two equations have been graphed in the attachment.

They intersected at (1,2).

The solution to the pair of equations is $x=1,y=2$

3 0

3 years ago

½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓ simplify IF NEEDED

Volgvan

Answer:

$( \frac{1}{2} x + 1 \frac{2}{3} ) - (1 \frac{1}{2} x - 1 \frac{1}{3} ) \\ = ( \frac{1}{2} - \frac{3}{2} )x + ( \frac{5}{3} + \frac{4}{3} ) \\ = \frac{ - 2}{2} x + \frac{9}{3} \\ = - x + 3 \\ = 3 - x$