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AlladinOne [14]
3 years ago
5

the sum of age of mabel and fred is 38 years,four years ago the age of mabel was the square of Fred age.Find their ages

Mathematics
1 answer:
Andrej [43]3 years ago
8 0

m+f=38

(f-4)^2=m-4

f^2=m IF their age is 30 combined

4^2=16

16=16

Fred is 4, Mabel is 16.

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Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?
Fofino [41]

Answer:

2500

Step-by-step explanation:

Let the first square number be x^2 then the next square number is (x+1)^2.

The difference between these two consecutive numbers is 99.

This implies that:

(x+1)^2-x^2=99

We expand to get:

x^2+2x+1-x^2=99

Simplify:

2x=99-1

2x=98

Divide both sides by 2

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Therefore the value of the larger perfect number is

(49+1)^2=50^2=2500.

6 0
3 years ago
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amid [387]

The answer is: 13-\frac{2}{9}g

The explanation is shown below:

1- You have the following expression given in the exercise:

(\frac{30}{45}g+20)-(\frac{8}{9}g+7)

2- When you multiply signs, you obtain:

\frac{30}{45}g+20-\frac{8}{9}g-7

3. Now, you must add like terms, as following:

-\frac{2}{9}g+13

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13-\frac{2}{9}g

8 0
3 years ago
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iren2701 [21]
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4 0
3 years ago
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mixer [17]

Answer:

10.5 feet

Step-by-step explanation:

In this problem, we have two similar triangles:

- One consists of the mailbox, its shadow and the hypothenuse

- The other one consists of the tree, its shadow and the hypothenuse

The two triangles are similar, so they have same proportions between their sides: therefore, we can apply the rule of three:

\frac{m}{s_m}=\frac{t}{s_t}

where

m = 36 in is the height of the mailbox

s_m=28 in is the shadow of the mailbox

t is the height of the tree

s_t=98 in is the length of the shadow of the tree

Solving for t, we find the height of the tree:

t=\frac{m\cdot s_t}{s_m}=\frac{(36)(98)}{28}=126 in

And since

1 feet = 12 inches

The height of the tree in feet is

t=\frac{126}{12}=10.5 ft

3 0
3 years ago
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Fed [463]

Answer:

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Step-by-step explanation:

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