3 gallons of strawberries.
3/4 * 4/1 = 12/4 = 3
or you can use the butterfly method on the fours and get
3/1 * 1/1 = 3
<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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Answer:
(hope this helps can I pls have brainlist (crown)☺️)
Step-by-step explanation:
In pic
Answer:
Step-by-step explanation:
A quadratic in factored form is usually expressed as: 
where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as: 
. Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)
I'll use the point (1, -4) the vertex
-4 = a(1+1)(1-3)
-4 = a(2)(-2)
-4 = -4a
1 = a. So yeah the value of a is 1
So the equation is just:
We can write and solve the differential equation that fits the statement given;
dy/dt = k(50-t)
∫dy = ∫ k(50-t)dt
= ∫ (50k - kt) dt
therefore;
y = 50kt - k/2(t²) + C
Alternatively, can be written as
y = - k/2 (50-t)² + C)
