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3 years ago

Please help i will mark brainliest (15 Points ) HELP PLEASE

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

The answer should be; 729 cm^3

ki77a [65]3 years ago

6 0

Answer:

729

Step-by-step explanation:

The sides of cubes are squares and the sides of squares are always the same length
L × W × H = V
9 × 9 × 9 = 729

I hope this helps!

You might be interested in

If 94 people attend a concert and tickets for adults cost $2.5 while tickets for children cost $1.75 and total receipts for the

Tasya [4]

Answer:

52 adults and 42 children attended the concert

Step-by-step explanation:

Given:

Total attendees=94 people

Adults tickets=$2.5

Children tickets=$1.75

Total receipts=$203.5

Let adults=a

Children=c

a+c=94 (1)

2.5a + 1.75c=203.5 (2)

From (1)

a+c=94

a=94-c

Substitute a=94-c into (2)

2.5a + 1.75c=203.5

2.5(94-c) + 1.75c=203.5

235-2.5c+1.75c=203.5

-0.75c=203.5-235

-0.75c=-31.5

Divide both sides by -0.75

-0.75c/-0.75=-31.5/-0.75

c=42

Substitute c=42 into (1)

a+c=94

a+42=94

a=94-42

=52

a=52

Therefore,

52 adults and 42 children attended the concert

3 0

3 years ago

How can 18/24 the fraction be written as a fraction

Ede4ka [16]

$\frac{18}{24} = \frac{6\times 3}{6\times 4} = \boxed{\frac{3}{4}}$

18/24 can be written as 3/4 in simplest form.

7 0

3 years ago

Read 2 more answers

Find the length and width of a rectangle.<br> Perimeter = 50<br> Side A = 3x + 2<br> Side B = x - 5

zmey [24]

Step-by-step explanation:

Perimeter = 2 * (Side A + Side B)

= 2 * (3x + 2 + x - 5)

= 2 * (4x - 3)

= 8x - 6.

We have 8x - 6 = 50, so 8x = 56 and x = 7.

Length of rectangle = 3(7) + 2 = 23.

Width of rectangle = (7) - 5 = 2.

4 0

3 years ago

Read 2 more answers

Im literally sitting here crying my eyes out because i have so much homework due tomorrow someone please just help me with this

skelet666 [1.2K]

Answer:

I'm sorry you have a lot of Homework. All i know is the 1st step... i believe their are 3 steps to this question, I wish you the best of luck my friend!

Step-by-step explanation:

1st step =

x=36

8 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago