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Ilya [14]
2 years ago
11

Please help me!

Mathematics
1 answer:
rewona [7]2 years ago
6 0

Answer:

12(j+t) + 15 = c

Step-by-step explanation:

So, lets go over what we know.

First off, for simplicity, lets consider Johnathan as J, and Trina as T.

We know that both J and T produce 12 dollars each per hour.

We know that J gets a extra 15 dollars.

We can think of the amount they produce each hour as the time they work in total, times the money they make a hour, which is 12.

We can think of this first part where the total time they work is (J + T)

The 12 dollars they get an hour can be though of as multiplying this sum: 12(J+T)

Finally, we know that J gets an extra 15 dollars.

This is not dependent on time, like the other variables, so we simply add it to the sum of what they make in the end:

12(J+T)+15

This looks like answer C.

Answer:

C

Hope this helps!

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See Explanation

Step-by-step explanation:

Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.

So, I'll make use of the following expression:

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When you follow the steps I'm about to provide, you'll arrive at the right answer

Required

Determine an equivalent expression

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Step 1: Take L.C.M of the denominators

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Step 2: Evaluate the fractions

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Step 3: Open the brackets at the numerator

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Step 4: Collect and evaluate like terms

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A TV show has 26 episodes. Due to the lack of time, you can onlywatch 5 of them. However, in order to get a gist of what the sho
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Answer:

Step-by-step explanation:

Recall that: The number of combination to select any k consecutive element from n consecutive term is given by the equation ^{n-k+1}C_k

= \begin {pmatrix} ^{n-k+1}_{k} \end {pmatrix}

where:

n = 26

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^{n-k+1}C_k= \begin {pmatrix} ^{26-5+1}_{5} \end {pmatrix}

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\mathbf{^{n-k+1}C_k=26334}

Therefore, there are 26334 selection of 5 episodes with no two consecutive episodes chosen

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4 years ago
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