Using the z-distribution, it is found that a sample size of 3,385 is required.
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
The margin of error is:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, we have a 98% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 2.327.
We have no prior estimate, hence is used, which is when the largest sample size is needed. To find the sample size, we solve the margin of error expression for n when M = 0.02, hence:
n = 3,385.
A sample size of 3,385 is required.
More can be learned about the z-distribution at brainly.com/question/25890103
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