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umka2103 [35]
3 years ago
12

The nth term of a sequence is represented by

B2n%5E3-11n%5E2-2n%2B17%7D" id="TexFormula1" title="\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}" alt="\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}" align="absmiddle" class="latex-formula"> . What is the limit of the nth term as x becomes increasingly large?
WILL GIVE BRAINLIEST, PLEASE ANSWER QUICKLY
Mathematics
1 answer:
Digiron [165]3 years ago
5 0

Answer:

2n3+8n2-32n=16

Step-by-step explanation:

2n3 +8n2-32n=16

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