Question

The nth term of a sequence is represented by B2n%5E3-11n%5E2-2n%2B17%7D" id="TexFormula1" title="\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}" alt="\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}" align="absmiddle" class="latex-formula"> . What is the limit of the nth term as x becomes increasingly large?
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Answer 1

Answer:

2n3+8n2-32n=16

Step-by-step explanation:

$2n3 +8n2-32n=16$