Answer:
178 chairs
Step-by-step explanation:
(something) rows of (something) columns always means to multiply. So, let's multiply 8 x 23:
8 × 23 = 184
Now, since the workers removed 6 of the chairs, there are 6 less chairs in the theater. Let's subtract 6 from 184 to get our final answer:
184 - 6 = 178
Hope this was helpful! Let me know if you have any other questions abou this problem. :)
Answer:
Inter quartile range.
Step-by-step explanation:
We have been given that the amount of money that college students spend on rent each month is usually between $300 and $600. However, there are a few students who spend $1,300.
We know that range, interquartile range, variance and standard deviation are the measures of spread.
Since $1300 is large valued outlier as mostly students spend between $300 and $600, so mean of our given data set will be grater than median and our given data is skewed to right.
Since range, variance and standard deviation are not good measure of spread for skewed data, therefore, inter-quartile range would be the most appropriate to measure the amount of money that college students spend on rent per month.
Answer:
0.0425
Step-by-step explanation:
probability of basket player = 0.25
probability of being a soccer player = 0.17
chances that a sixth grader plays basketball AND soccer = 0.25×0.17 = 0.0425
First off, we factor out the expression:

In the bracket, separate 8 out of the expression.
![\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 8)] }\\ \displaystyle \large{y = 2[ ( {x}^{2} - 6x) + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%20%2B%208%29%5D%20%7D%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%29%20%2B%208%5D%7D)
In x^2-6x, find the third term that can make up or convert it to a perfect square form. The third term is 9 because:

So we add +9 in x^2-6x.
![\displaystyle \large{y = 2[ ( {x}^{2} - 6x + 9) + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%28%20%7Bx%7D%5E%7B2%7D%20-%206x%20%2B%209%29%20%20%2B%208%5D%7D)
Convert the expression in the small bracket to perfect square.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20%2B%208%5D%7D)
Since we add +9 in the small bracket, we have to subtract 8 with 9 as well.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} + 8 - 9]} \\ \displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20%2B%208%20-%209%5D%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D)
Then we distribute 2 in.
![\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D%20%5C%5C%20)
![\displaystyle \large{y = 2[ {(x - 3)}^{2} - 1]} \\ \displaystyle \large{y = [2 \times {(x - 3)}^{2} ]+[ 2 \times ( - 1)] } \\ \displaystyle \large{y = 2 {(x - 3)}^{2} - 2 }](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%5B%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20%20-%201%5D%7D%20%5C%5C%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%20%5B2%20%5Ctimes%20%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%5D%2B%5B%202%20%5Ctimes%20%28%20-%201%29%5D%20%7D%20%5C%5C%20%5Cdisplaystyle%20%5Clarge%7By%20%3D%202%20%7B%28x%20-%203%29%7D%5E%7B2%7D%20%20-%202%20%7D)
Remember that negative multiply positive = negative.
Hence the vertex form is y = 2(x-3)^2-2 or first choice.
Its very simple. Every triangle has a maximum degree of 180°.
We can substract all of the given angles to get our x angle, like so:
x = 180 -102 - 39 = 39°