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Olenka [21]
3 years ago
14

GEOMETRY HELP PLEASE!

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

(1, 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

C(1, - 2 )  → C'(1, 2 )

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Which of the following is not a career in environmental science? a. Hydrologist b. Toxicologist c. Physiologist d. Ecologist Ple
kodGreya [7K]

Answer:

C

Step-by-step explanation:

No doubt thats the correct answer guys, thank me later

6 0
3 years ago
~~~~~~~~~~~`````````````````
bixtya [17]

Answer:

Step-by-step explanation:

(-3/4)x + 9 = (-1/2)x + 8

        9 - 8 =  (-1/2)x + (3/4)x

               1 =  (1/4)x

              x = 4

y = (-3/4)4 + 9

y = -3 + 9

y = 6

3 0
3 years ago
Segment AE is a median for Triangle ABC.
Shalnov [3]

Step-by-step explanation:

BC = BE + CE...(\because B-E-C)  \\  \\  \therefore \: BC = 3x - 5 + x + 1 \\  \\ \therefore \: BC = 4x - 4 \\  \\  \huge \red{ \boxed{ \therefore \: BC = 4(x - 1)}}

4 0
4 years ago
What whole number dimensions would allow the students to maximize the volume while keeping the surface area at most 160 square f
ycow [4]

Answer:

The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft

Step-by-step explanation:

Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²

For maximum volume, the side length, s of the cube must all be equal ;

Therefore area of one side = s²

Number of sides in a cube with top open = 5 sides

Area of surface = 5 × s² = 180

Therefore s² = 180/5 = 36

s² = 36

s = √36 = 6 ft

Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.

6 0
3 years ago
If 3x+2=5/9, what is the value of −3x+8?<br><br>Group of answer choices
allsm [11]

Answer:

= 4

Step-by-step explanation:

first lets find the value of x in 3x+2=5/9

3x+2=5/9

3x = \frac{5}{9} -2

3x = \frac{3}{9}

3x = \frac{1}{2}

x = \frac{1}{2 * 3\\ }

x = \frac{1}{6}

\frac{1}{6} can also be written as 6^{-1}

−3x+8

-3 (\frac{1}{6}) +8

\frac{-3}{6} +8

= 4

3 0
3 years ago
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