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vampirchik [111]

3 years ago

12

What is the value of (Negative one-half)–4?

2 answers:

Montano1993 [528]3 years ago

5 0

The answer is D) 16.

ivanzaharov [21]3 years ago

4 0

I’m assuming you mean -1/4 -4, and since you’re subtracting a negative by a negative, it would be -4 1/4(mixed number)

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stepladder [879]

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to arrive at 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution. How many liters of eac

CaHeK987 [17]

Answer:

<u>800 liters</u> of 90% saline solution and <u>1200 liters</u> of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

<u><em>Let the liters of 90% saline solution mix be </em></u> $x.$ <u><em /></u>

<u><em>And let the liters of 40% saline solution mix be</em></u> $y.$

So, the total number of liters:

$x+y=2000.$

$y=2000-x\ \ \ ....(1)$

Now, the total percentage of saline solution:

$90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000$

$\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000$

$0.9x+0.4y=1200$

Substituting the value of $y$ from equation (1) we get:

$0.9x+0.4(2000-x)=1200$

$0.9x+800-0.4x=1200$

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Subtracting both sides by 800 we get:

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Dividing both sides by 0.5 we get:

$x=800.$

<u>The liters of 90% saline solution mix = 800.</u>

Now, substituting the value of $x$ in equation (1) to get the liters of 40% saline solution:

$y=2000-x$

$y=2000-800$

$y=1200.$

<u>Thus, the liters of 40% saline solution = 1200.</u>

Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

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sergij07 [2.7K]

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