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Ymorist [56]
3 years ago
5

Which graph represents the solution to the system of inequalities?

Mathematics
2 answers:
sattari [20]3 years ago
6 0
Here is an image of that

diamong [38]3 years ago
3 0

Solution:

we are given with the system of equation:

x + y ≥ 4

2x + 3y < 12

we have been asked to find the graph representing the solution of the given system of equation.

To find the the solution of the given system of inequalities, we can draw the graph using a graphing calculator and thereafter , the point of intersection will give the solution of the given system of equation.

As we can see, the graph is intersecting at only one point at (0,4).

The given system of inequalities will have infinite number of solutions and it will fall in the region shaded with green.


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Based on the data gathered should Brenda choose if she is in a hurry
Ad libitum [116K]
What??????????????????????????????????

5 0
4 years ago
Factor:<br> -2 +8=-20<br> THANKS IN ADVANCE!!!
Anettt [7]

Answer:

-2 +8=-20 False

Step-by-step explanation:

Simplify -2 +8 --> 6

6= -20 is False

^      ^

sides arent equal

4 0
3 years ago
An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he
timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, d_1 = 1\times610=610 miles.

The distance covered at 310 degrees, d_2 = 3\times610=1830 miles.

Total distance covered, d, is the magnitude of the sum of vectors \vec{d_1} and \vec{d_2} as shown in the figure.

The angle between the vectors \vec{d_1} and \vec{d_2}, \theta=310-270=40 degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}

\Rightarrow d=2330.51 miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0
3 years ago
Question 1 (1 point)
salantis [7]
Blank 1: 1

Blank 2: 3

Blank 3: -2
3 0
3 years ago
I need help with 10,11,12
pshichka [43]
10. 50 is roughly around ~16% of 300. (16% is 50.1)

11. 35% of 150 would be 52.5

12. 80 is 200% of 40

3 0
3 years ago
Read 2 more answers
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