Answer:
Probably c
Step-by-step explanation:
Tbh
Answer:
<h3>⭐In a unit rate, the denominator is always 1. So, to find unit rate, divide the denominator with the numerator in a way that the denominator becomes 1. For example, if 50km is covered in 5.5 hours, the unit rate will be 50km/5.5 hours = 9.09 km/hour.</h3>
Step-by-step explanation:
<h2>⛄I hope it's helpful for you ⛄</h2>
Answer:
2.83 s
Step-by-step explanation:
We are given that

When a rock reached the ground then h(t)=0


Using quadratic formula





Time cannot be negative .Therefore, negative value of t can not be possible.
Hence, the rock takes 2.83 sec to reach the ground.
Answer:
5
Step-by-step explanation:
An area is just a number squared, so we need to find the square root of the area.
Square root of 25 = 5
So each edge is 5 feet.
Hope this helps :)
Answer:
sorry I just needed points
Step-by-step explanation:
dndjdjdnsnsnsuxknsdu djdjebheu suss hsshsb yshebejdb usjsne