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trapecia [35]
3 years ago
12

Rearrange x=3g+2 to make g the subject

Mathematics
2 answers:
Alecsey [184]3 years ago
7 0
(x-2)/3 =g the parenthesis are important
Rashid [163]3 years ago
3 0
x =   3g + 2
- 2          - 2
x - 2 = 3g
÷ 3       ÷ 3

x - 2 ÷ 3 = g
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Your teacher took a survey of student’s eye colors. She found that 15 students have brown eyes, 6 students have green eyes, and
svetlana [45]
Brown- 15
Green- 6
Blue- 4

15+6+4= 25
5 0
3 years ago
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There were 137 adult dusky gopher frogs in 2014. The number of adult dusky gopher frogs has grown about 9% per year since then.
Neporo4naja [7]

Answer:

273 frogs.

Step-by-step explanation:

The equation of growth in the number of frogs N = 137(1.09)^t where t is the time in years.

The year 2022 is 8 years after 2014 so the prediction for N in 2022 is:

N = 137(1.09)^8 = 273.

4 0
3 years ago
Is 1/2 and 0.5 the same?
Tanzania [10]

Answer:

Yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?
Zolol [24]

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

According to the given question.

The total number of elements, n = 3

The number of elements to be selected at a time when repetition is  allowed, r = 5

Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is n^{r}.

Therefore,

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed

= 3^{5}

= 243

Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

Find out more information about permuations here:

brainly.com/question/13833229

#SPJ4

3 0
1 year ago
HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)
meriva

Given:

x-intercepts of the hyperbola are ±4.

The foci of hyperbola are \pm 2\sqrt{5}.

Center of the hyperbola is at origin.

To find:

The equation of the hyperbola.

Solution:

The general equation of a hyperbola:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1            ...(i)

Where, (h,k) is the center of the hyperbola, ±a are x-intercepts, (\pm c,0) are foci.

Center of the hyperbola is at origin. So, h=0 and k=0.

x-intercepts of the hyperbola are ±4. So,

\pm a=\pm 4

a=4

The foci of hyperbola are \pm 2\sqrt{5}.

\pm c=\pm 2\sqrt{5}

c=2\sqrt{5}

We know that,

a^2+b^2=c^2

(4)^2+b^2=(2\sqrt{5})^2

16+b^2=20

b^2=20-16

b^2=4

Taking square root on both sides, we get

b=\sqrt{4}                    [b>0]

b=2

Substituting h=0,k=0,a=4,b=2 in (i), we get

\dfrac{(x-0)^2}{4^2}-\dfrac{(y-0)^2}{2^2}=1

\dfrac{x^2}{4^2}-\dfrac{y^2}{2^2}=1

Therefore, the correct option is (d).

4 0
3 years ago
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