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3 years ago

Solve two fifths minus one seventh equals blank

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

3 0

The answer should be 9/35

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Help me please. Im giving 20 points

liraira [26]

Answer:

36 meters away

Step-by-step explanation:

If you look at the equation you'll see that Cody is 16 meters away from Brenda and Lara is 20 meters away from Brenda, so if you add those two, you'll get the answer. :)

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4 years ago

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Write and solve a measure of each angle.

aliya0001 [1]

They both are acute angles

8 0

3 years ago

The surface area of a cube is 600 square inches. What is the area of one of its faces?

wel

Answer:

Area of one face of the cube is $100 inches^2$

Step-by-step explanation:

A cube is a three dimensional figure that has all of its sides equal.

A cube has six square faces:

Surface area of the cube = $6a^2$

where 'a' is the side length of the cube:

Area of one face of a cube= $a^2$

For surface area of the whole cube: 500 square inches

$6a^2=600$

Dividing by '6' both sides;

$a^2=600/6\\\\$

$a^2=100inches^2$

Area of one face of the cube is $100 inches^2$

7 0

3 years ago

PLEASE HELP AND EXPLAIN STEP BY STEP.

SIZIF [17.4K]

A. The two listed added up will be 180 degrees.

5x - 57 + 3x + 5 = 180

8x - 52 = 180

8x - 52 + 52 = 180 + 52

8x = 232

x = 29

B. The two listed added up will be 180 degrees.

2x + 4x + 150 = 180

6x + 150 = 180

6x + 150 - 150 = 180 - 150

6x = 30

x= 5

Can I get brainlyist

8 0

3 years ago

A factory is to be built on a lot measuring 210 ft by 280 ft. A local building code specifies that a lawn of uniform width and e

Tresset [83]

Answer:

Width of lawn = 35 ft

Dimensions of factory = length: 210 ft, width: 140 ft

Step-by-step explanation:

The total area of the lot can be calculated as:

$A_{lot} = 210 * 280\\A_{lot} = 58800 ft^{2}$

Since, the area of factory should be equal to area of lawn:

$A_{lot} = A_{factory} + A_{lawn}\\58800 = 2 A_{factory or lawn}\\\\A_{factory or lawn} = \frac{58800}{2}\\A_{factory or lawn} = 29400 ft^{2}$

Now, let 'x' be the width of lawn, the dimensions of factory can be written as:

$(210-2x)\\(280-2x)\\$

Since, area is equal to length x width:

$(210-2x)*(280-2x) = 29400\\Simplifying:\\210*280 - 210*2x - 2x*280 + 4x^{2} = 29400\\58800 - 420x - 560x +4x^{2} = 29400\\4x^{2} - 980x +58800 = 29400\\4x^{2} - 980x + 29400 = 0\\$