5x ÷ x² - 9 + 7 ÷ x + 3
Write the division as a fraction:
- 9 +
+ 3
Simplify the expression:
- 9 +
+ 3
Calculate the sum:
- 6 +
Write all numerators above the common denominator:
Add the numbers and you get the final answer:
How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?
1 answer:
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
According to the given question.
The total number of elements, n = 3
The number of elements to be selected at a time when repetition is allowed, r = 5
Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is .
Therefore,
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed
=
= 243
Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
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Answer:
f(-4) = 4
Step-by-step explanation:
Fro the graph attached,
We have to calculate the value of the function at x = -4.
As we can find from the graph at the input value x = -4, output value of the function is f(-4) = 4
Therefore, f(-4) = 4 will be the answer.
