How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?
1 answer:
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
According to the given question.
The total number of elements, n = 3
The number of elements to be selected at a time when repetition is allowed, r = 5
Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is .
Therefore,
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed
=
= 243
Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
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The values are a = 7, b = -9, c = -18.
<u>Step-by-step explanation:</u>
The given quadratic equation is
The general form of the quadratic equation is
where,
- a is the coefficient of x².
- b is the coefficient of x.
- c is the constant term.
Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.
So, bring the constant term 18 to the left side of the equation for equating it to zero.
⇒
Compare the above equation with general form
⇒ a = 7
⇒ b = -9
⇒ c = -18
Therefore, the values of a, b, and c are 7, -9 and -18.