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k0ka [10]
1 year ago
6

How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?

Mathematics
1 answer:
Zolol [24]1 year ago
3 0

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

According to the given question.

The total number of elements, n = 3

The number of elements to be selected at a time when repetition is  allowed, r = 5

Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is n^{r}.

Therefore,

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed

= 3^{5}

= 243

Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

Find out more information about permuations here:

brainly.com/question/13833229

#SPJ4

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Answer:

Batch 1:  Pineapple = 3 1/2; Banana = 1 2/5

Batch 2:  Pineapple = 8; Coconut = 4 4/5

Batch 3:  Banana = 1; Coconut = 1 1/2

Step-by-step explanation:

For Batch 1:

We know that coconut is 3/10 of the mixture, and we have 2 1/10 coconut:

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1/5 is banana:  1/5(7) = 7/5 = 1 2/5

For Batch 2:

1/5 of the total is banana; we have 3 1/5 banana:

1/5x = 3 1/5

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1/5x = 16/5

Divide both sides by 1/5:

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Flip the second fraction and multiply:

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Coconut is 3/10 of the total:

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Pineapple is 1/2 of the total.  We have 2 1/2 pineapple:

1/2x = 2 1/2

Convert the fraction on the right to improper:

1/2x = 5/2

Divide both sides by 1/2:

1/2x÷1/2 = 5/2÷1/2

Flip the second fraction and multiply:

x = 5/2×2/1 = 10/2 = 5

We have 5 total shampoo.

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Coconut is 3/10 of this:

3/10(5) = 15/10 = 1 5/10 = 1 1/2

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