All categories

3 years ago

Identify the fungus type pictured below.

Biology

2 answers:

kap26 [50]3 years ago

7 0

sac fungi is the answer

Vika [28.1K]3 years ago

3 0

Answer:

Sac fungi

Explanation:

The species of the figure is a fungus of the Ascomycota phylum (Sac fungi) belonging to the Pezizaceae family, whose characteristic is the production of mushrooms in a bowl-like shape. This shape allows the spores inside the mushroom to be dispersed when water enters this "bowl".

You might be interested in

Which of the following is not one of the seven primary odors humans recognize?

natulia [17]

Answer:

roses

Explanation:

It occurs when an odor binds to a receptor within the nasal cavity, transmitting a signal through the olfactory system.2 Glomeruli aggregate signals from these receptors and transmit them to the olfactory bulb, where the sensory input will start to interact with parts of the brain responsible for smell identification, memory, and emotion.3

There are many different causes for alteration, lack, or disturbance to a normal sense of smell, and can include damage to the nose or smell receptors, or central problems affecting the brain. Some causes include upper respiratory infections, traumatic brain injury, and neurodegenerative disease.

8 0

3 years ago

Read 2 more answers

Which fertizer element is of most concern environmentally?

andre [41]

It would be Phosphorus

6 0

3 years ago

In a population of 150 toads, poisonous (P) is dominant over non-poisonous (p). According to the Hardy-Weinberg equation, the ex

aalyn [17]

Answer: Χ²=8.18

Explanation: In this population, the frequency of homozygote poisonous toads is:

$p^{2} =\frac{100}{150}$

$p^{2} = 0.667$

$p = \sqrt{0.667}$

p=0.82

For the homozygote non-poisonous toads:

$q^{2} = \frac{5}{150}$

$q^{2} =0.034$

$q = \sqrt{0.034}$

q = 0.18

The frequency for heterozygote poisonous toad, we can use the Hardy-Weinberg equation: $p^{2} + 2pq + q^{2} = 1$ , in which, heterozygote frequency is given by 2pq

2pq = 2*0.82*0.18 = 0.3

Now, to compute the chi-square test, follow the instructions:

1) Find the observed values: in this case, they are the found frequency:

0.82 0.3 0.18

2) Find the expected values: As the question mentioned, the expected proportion is:

16 8 1

3) Subtract the observed value from the expected value:

0.82 - 16 = - 0.184 0.3 - 8 = -7.7 0.18 - 1 = - 0.818

4) Square each value from above:

(-0.184)² = 0.034 (-7.7)² = 59.3 (-0.818)² = 0.77

5) Divide each value by expected value:

$\frac{0.034}{16}$ = 0.0021 $\frac{59.3}{8}$ = 7.41 $\frac{0.77}{1}$ = 0.77

6) Add all the values and we will have the chi-square test:

Χ² = 0.0021 + 7.41 + 0.77 = 8.18

The chi-square test is Χ² = 8.18

8 0

3 years ago

In diffusion, movement of particles across a membrane is driven by differences in

mote1985 [20]

C. concentration; moves from areas of high concentration to areas of low\

3 0

3 years ago

Read 2 more answers

In the United States, mothers who live in poverty generally have babies with lower birthweight than those who do not live in pov

earnstyle [38]

Answer:

The correct answer is paired sample t-test.

Explanation:

Based on the given information, the mothers living in poverty in the United States give birth to underweight babies. The average weight of the babies given birth by women living in poverty is 2.8 kg. To examine the efficacy of a novel prenatal care program, a test was conducted by the CDC in which 30 mothers living in poverty and the weights of their babies were recorded.

As the test is conducted in pairs, thus, paired sample t-test would be the appropriate hypothesis test. The paired t-test is performed when the dependent variable is measure spontaneously. In the given case, the women participating in the program and the number of babies with less birth weight are examined in pairs. Thus, as the sample are paired together, the correct answer would be paired sample t-test.

6 0

4 years ago