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ValentinkaMS [17]
3 years ago
5

Please help me on this one thank you

Biology
1 answer:
BlackZzzverrR [31]3 years ago
4 0
The answer to 20. is A.
B wouldn't affect the plates,
C would push the plates downwards,
and D.... I don't even know what that is.
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Write an essay about roundgaint worm​
Leokris [45]
<h2>Roundworms are among the most <u>numerous creatures</u> on the planet.</h2>

  • Roundworms may survive for a lengthy time throughout the human gut. They can be dangerous as well as end up causing a variety of issues, including abdominal discomfort, fever, as well as <u>diarrhea</u>.
  • Roundworms have long, round bodies that vary throughout the size depending on the species.

Thus the response above is right.

Learn more about roundworm here:

brainly.com/question/23560105

7 0
2 years ago
Read 2 more answers
Based on the trilobite fossil, what can you infer about the rock layers in these location? Layer a is 500 million years old. Lay
frozen [14]

Answer: Layer a is 500 million years old.

Explanation:

Trilobite is a member of the group of extinct arthropods found as fossils and they can be identified by the three-lobed as well as three segmented forms. These were the marine animals. These were appeared initially in the Cambrian Period. They used to live 542 million years ago so the fossils can be estimated to be aged of 500 above years old. These animals used to dominate in the sea area.

5 0
2 years ago
Which property results from the crystal lattice structure of ionic compounds? A. low melting point B. good electrical conductivi
lions [1.4K]

Answer:

C.) crystalline solids

Explanation:

The solid materials may be crystalline or amorphous. The concept of crystal structure is related to the organization of atoms in a geometrical form. Crystalline structures are present in various materials, where atoms distributed within their structure form a network called the crystalline lattice. Therefore, crystalline structures have salts, metals and most minerals. Crystalline structures are formed by unit cells that are their basic unit, as they constitute the smallest set of associated atoms found in a crystalline structure.

The molecules of the crystalline structures can have two types of bonds, the directional ones, which include the covalent and dipole dipole and the non-directional ones where the metallic, ionic, van der Walls bonds. When formed by ionic compounds, these crystalline structures can result in crystalline solids.

5 0
3 years ago
An air pressure of 1,005 millibars is equivalent to approximately how many inches of Mercury?
N76 [4]

1005milibars of pressure corresponds to 29.68inches of mercury.

Option D.

<h3><u>Explanation:</u></h3>

Mercury has a density of around 13.6gm/cc. Thus the pressure of inches of mercury will have a huge effect on the value. As far as bar is concerned, it's around the normal atmospheric pressure measured at sea level. Its around 1,00,000 pascals. So from converting a pressure at millibars to inches of mercury, we need to divide the value by a factor of 33.864.

So, pressure in milibars =1005milibars.

So, pressure in inches of mercury = 1005/33.864 = 29.68 inches of mercury.

6 0
3 years ago
Nuclear envelope forms at each pole spindle dissolves chromosomes uncoil. True or False
Doss [256]

Answer:

True.

Explanation:

There are four phases which occur during karyokinesis, these are -

  • Prophase
  • Metaphase
  • Anaphase
  • Telophase

Telophase is the last phase of karyokinesis. The main events that occur during telophase are-

  • Uncoiling of chromosome occurs
  • Chromatin is formed
  • Spindle breaks down
  • Nuclear membrane or nuclear envelope if reformed

Thus it is clear that the events that are mentioned in the question denote truly about the Telophase.

4 0
3 years ago
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