Please help me on this one thank you
1 answer:
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Answer:
b
Explanation:
First, let us look at the result of crossing the two genotypes Mmpp and mmpp.
Mmpp will give the gametes Mp, Mp, mp, and mp
mmpp will give the gametes mp, mp, mp, and mp
The two sets of gametes can thus be lined up on both axis of the Punnet's square as shown in the attached image.
Genotypes of the offspring: 8 Mmpp and 8 mmpp
<u>Since the two genes follow simple Mendelian inheritance pattern, the 2 genotypes automatically equates to 2 phenotypes in the ratio 1:1.</u>
<em>Hence, the correct option is </em><em>b</em><em>.</em>
Answer:
0
Explanation:
Let's assume that the gene coding for tongue rolling is encoded by letter T.
The allele for tongue rolling (T) is dominant over the allele for inability to roll the tongue (t).
In a cross between two homozygous dominant individuals (TT) i.e. they have the same dominant allele in their genotype and hence, they can both roll their tongues.
(See attached image)
The cross will produce four possible offsprings, in which all will possess a homozygous dominant genotype i.e. all will be phenotypically able to roll their tongues. Hence, in the case of the child, the child will be able to roll his tongue.
The probability or chance that the child will be unable to roll his tongue is 0. Since there is none.
