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guapka [62]
3 years ago
11

I NEED THE ANSWER PRONTO CUZ I'M DOING THE TEST RIGHT NOW!!!!!Devon made the scatter plot to track his bank balance over time.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
It should be <span>y=15x+250</span>
You might be interested in
What are two rational numbers between -3/4 and -2/3​
Vadim26 [7]

The two rational numbers between -  \frac{3}{4}and -  \frac{2}{3}is -  \frac{32}{48},-  \frac{36}{48}

<h3>How to find the rational numbers between -3/4 and -2/3?</h3>

In the form of p/q, which can be any integer and where q is not equal to 0, is expressed as rational numbers. As a result, rational numbers also contain decimals, whole numbers, integers, and fractions of integers (terminating decimals and recurring decimals).

given that -3/4 and -2/3

now take L.C.M between these two rational numbers is 12.

now multiply -3/4 with 3 both numerator and denominator

-  \frac{3}{4}  \times  \frac{3}{3}  =   - \frac{ 9}{12}

again multiply -9/12 with 4 both numerator and denominator

-  \frac{9}{12}  \times  \frac{4}{4}  =  -  \frac{36}{48}

now multiply -2/3 with 4 both numerator and denominator

-  \frac{2}{3}  \times  \frac{4}{4}  =  -  \frac{8}{12}

again multiply -8/12 with 4 both numerator and denominator

-  \frac{8}{12}  \times  \frac{4}{4}  =  -  \frac{32}{48}

Hence the -36/48 and -32/48 are rational numbers between -3/4 and -2/3

Learn more about rational numbers, refer:

brainly.com/question/12088221

#SPJ9

8 0
1 year ago
The vertices of AMNO are M (1,3), N (4,9), and O (7,3). The vertices of APQR are P (3,0), Q (4,2), and R (5,0) Which conclusion
Pavel [41]

Answer:

the correct answer should be C

Step-by-step explanation:

hope this helps you

3 0
3 years ago
Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba
nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

n = 12, p = 0.5

(a) 2 or 5 children

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208

P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537

P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161

P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029

P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0
3 years ago
English
larisa86 [58]

Answer:

6 square feet

Step-by-step explanation:

Carpet has w= 8 ft and l = 12 ft

Reduced carpet has w' = 2 ft

<u>Reduction factor is </u>

  • 8/2 = 4

<u>Then </u>

  • l' = l/4 = 12/4 = 3 ft

<u>Area of small carpet</u>

  • S = 2*3 = 6 ft²
6 0
3 years ago
How to write the equation in standard form using 5x-y+6=0
irga5000 [103]
5x-y=6
Use the formula!
8 0
3 years ago
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