Answer:
Step-by-step explanation:
Consider the revenue function given by 
. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).
From the first equation, we get, 
.If we replace that in the second equation, we get
From where we get that 
. If we replace that in the first equation, we get
So, the critical point is 
. We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that
We have the following matrix,
![\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Bmatrix%7D%20-10%20%26%20-2%20%5C%5C%20-2%20%26%20-16%5Cend%7Bmatrix%7D%5Cright%5D)
.
Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is 
and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum
Do you mean 'nine and eighty four hundredths' in standard form? If so, it will be:
9.84
Answer:
give me sec waitttttttt give me sec is their any answer choice
Considering it's vertical asymptote, the rational function graphed below is given by:
A. 
.
<h3>What are the vertical asymptotes of a function f(x)?</h3>
The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
In this graph, there is a vertical asymptote at x = 4, that is, x - 4 is a term of the denominator, hence the function is given by:
A. .
More can be learned about vertical asymptotes at brainly.com/question/16948935
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