Do number 4 please DONT get it wrong or i block report, i really need help please :)
1 answer:
Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle =
Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
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for x (subtract 1 from both sides; then divide both sides by 2). I set 2x+1 larger or equal to 0 because we want to avoid the stuff under the square root to be negative.
If you want the domain in interval notation, then it would be which means the interval starts at -1/2 (including -1/2) and then it stops at infinity. So technically it never stops and goes on forever to the right.
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Part b.
I'm going to use "sqrt" as shorthand for "square root"
f(x) = sqrt(2x+1)
f(10) = sqrt(2*10+1) ... every x replaced by 10
f(10) = sqrt(20+1)
f(10) = sqrt(21)
f(10) = 4.58257569 which is approximate
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Part c.
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f(x) = sqrt(2(x)+1)
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we can't simplify any further
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Hope that helps!