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lilavasa [31]
3 years ago
14

I need someone to talk to i can watch socials till i finish 85 assignments/ 27 hours in on day

Mathematics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

woah well good luck with that and its finals week for me so pray for me pls!

and i will pray for you:)

mestny [16]3 years ago
5 0
???"??????????? What
You might be interested in
Val walks 2 3/5 miles each day.bill runs 10 once every 4 days.in 4 days.who covers the greater distance?
Mkey [24]

Answer: Val walks the greater distance. She walks 2/5 miles more than Bill. Hope this helps!

Step-by-step explanation:

6 0
3 years ago
True or False: The angle opposite a side length of 6 cm in a triangle is larger than an angle opposite a side length of 7 cm in
kipiarov [429]

Answer:

False

Step-by-step explanation:

The angle opposite the longest side is the largest

The angle opposite the shortest side is the smallest

So the angle opposite 6 cm is smaller than the angle opposite 7 cm

3 0
2 years ago
Read 2 more answers
In a newspaper, it was reported that yearly robberies in Springfield were down 30% to 91 in 2013 from 2012. How many robberies w
Artyom0805 [142]

Answer:

130

Step-by-step explanation:

3 0
3 years ago
How do you solve his with working
AlexFokin [52]
Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888



b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884

7 0
3 years ago
What is one more unit then 5 tenths
spin [16.1K]

Answer:

i think it is 1.5

Step-by-step explanation

because 5 tenths is equal .5 and adding 1 unit which is adding on one which should equal 1.5

3 0
3 years ago
Read 2 more answers
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