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aniked [119]
2 years ago
6

Find surface area of rectangular prism

Mathematics
1 answer:
DIA [1.3K]2 years ago
5 0

Answer:

806 yd sq.

Step-by-step explanation:

Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.

They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.

You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.

The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.

Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.

Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.

Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.

The surface area would be 806 yd sq.

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Find the value of the unknown.
Daniel [21]

Answer:

86.5

14 + 8 + 12.5 = 34.5 \:  \: 121 - 34.5 = 86.5

4 0
3 years ago
a triangle has two sides of lenghts 7 and 12 what value could the length of the third side be check all that apply
Bond [772]
Third length =

12-7 = 5
12+7 = 19

Third length can be only in this range

5Means the third length must be greater than 5 and less than 19.


Hope this helps!
3 0
3 years ago
Read 2 more answers
Please help me I honestly have zero clue how to answer this question
Iteru [2.4K]

Step-by-step explanation:

n = 3 \times 5 {}^{2}   \times  {x}^{3}

Square both sides of the equation.

{n}^{2}  = (3 {}^{2}  \times 5 {}^{4}  \times  {x}^{6} )

5 {n}^{2}  = 5(3 {}^{2}  \times  {5}^{4}  \times  {x}^{6} )

6 0
3 years ago
A line that includes the point (4,1) has a slope of 1 7 . What is its equation in point-slope form?
Sergeeva-Olga [200]

Answer:

y = 17x-67

Step-by-step explanation:

The one point form of line also called slope point form is given by

(y-y_1)=m(x-x_1)

where (x1, y1) is the point and m is slope

Given: (x1, y1) = (4,1) and m= 17

Substituting these values in above equation to find equation in point-slope form

(y-1)=17(x-4)

y-1 = 17x-68

y = 17x-67

the point -slope form of equation y = 17x-67

5 0
2 years ago
If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?
Nuetrik [128]

Answer:

Density of material would be 4.09 g/cm^3

units is g/cm^3

Step-by-step explanation:

Given: The mass of a material is 45 grams and the volume of the material is 11 cubic centimeter

Density is defined as mass per unit volume.

It is given by:

p= \frac{m}{V} where p is the density , m is the mass and V is the volume of the material respectively.

Here, Density is expressed in grams per centimeter cubed (g/cubic cm)

Here, m = 45 g , V = 11 cubic cm

We get;

p= \frac{45}{11} = 4.09 g/cm^3

therefore, density of a material would be, 4.09 g/cm^3

and its units is g/cm^3

7 0
3 years ago
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