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1 year ago

Find surface area of rectangular prism

Mathematics

1 answer:

DIA [1.3K]1 year ago

5 0

Answer:

806 yd sq.

Step-by-step explanation:

Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.

They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.

You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.

The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.

Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.

Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.

Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.

The surface area would be 806 yd sq.

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2 years ago

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2 years ago

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Dahasolnce [82]

Answer:

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Step-by-step explanation:

Given the following data;

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2 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

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Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

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By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

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simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

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2 years ago

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