Answer:
its G. and J
Step-by-step explanation:
Answer:
there
Step-by-step explanation:
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
It would be at 35 when you work all then problems together
You can solve the median by putting all the numbers in order. Then cross off one at a time at the start, then cross off the one at the end, then keep going until you get to one.
You can solve the mode by looking for the most frequent number. I remembered that by looking at mode and seeing MO and remembering most often.
I hope this helps :-)
