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3 years ago

5

Three vertices of square WXYZ are W(1, 4), X(4, 0), and Y(0, –3). What are the coordinates of the fourth vertex?

1 answer:

BARSIC [14]3 years ago

8 0

Hello,

Z=(-3,1)
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Which decimal is equivalent to

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You're answer is B.) 0.7 because both the fraction and the decimal read seven tenths.

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Use the net to compute the surface area of the three-dimensional figure. A) 210 units B) 225 units C) 240 units D) 280 units

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The answer would most commonly be C only because a square is 360 degrees and the surface area would be a 6th of that which is 60 then i multiplied it by 4 because of the four corners signaling the height and or length of the 2D figure square which gives me C.

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3 years ago

An arched drainage culvert can be modelled by the function:

Zanzabum

Substitute 136.5 for y.

$136.5=\frac{x(191-x)}{60}$

$8190=x(191-x)$

$8190=191x-x^{2}$

$x^{2} -191x+8190=0$

Compare this equation with $ax^{2} +bx+c=0$

a = 1, b = - 191, c = 8190

$x=\frac{-b+\sqrt{b^{2}-4ac } }{2}$ or

$x=\frac{-b-\sqrt{b^{2}-4ac } }{2}$

$x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2}$ or

$x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}$

$x=\frac{191+\sqrt{36481-32760 } }{2}$ or

$x=\frac{191-\sqrt{36481-32760 } }{2}$

$x=\frac{191+\sqrt{3721 } }{2}$ or

$x=\frac{191-\sqrt{3721 } }{2}$

$x=\frac{191+61}{2}$ or

$x=\frac{191-61}{2}$

$x=\frac{252}{2}$ or

$x=\frac{130}{2}$

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = $\sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}$

= $\sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}$

= 126 - 65

= 61

Hence, width of the air space is 61m.

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3 years ago

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Answer:

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Step-by-step explanation:

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9514 1404 393

Answer:

A. (4, 12)

Step-by-step explanation:

Adding the second equation to twice the first will eliminate y.

2(10x +2y) +(3x -4y) = 2(64) +(-36)

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This value matches choice A: (4, 12).

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