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3 years ago

Determine if the following table represents a quadratic function.

Mathematics

1 answer:

snow_tiger [21]3 years ago

7 0

Answer:

The options are not visible enough (See Explanation)

Step-by-step explanation:

Given

x:- 1 || 2 || 3 || 4 || 5

y:- 13 || 22 || 37 || 58 || 85

Required

Determine if the function is quadratic

Calculate the difference between the values of y

$Difference = 22 - 13 = 9$

$Difference = 37 - 22 = 15$

$Difference = 58 - 37 = 21$

$Difference = 85 - 58 = 27$

The resulting difference are: 9 || 15 || 21 || 27

Next; Calculate the difference between the difference of values of y

$Difference = 15 - 9 = 6$

$Difference = 21 - 15 = 6$

$Difference = 27 - 21 = 6$

The resulting difference are: 6 || 6 || 6

For the function to be quadratic, the above difference must be the same and since they are the same (6), then the function represents a quadratic function.

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Answer:

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Step-by-step explanation

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3 years ago

How to Solve -5x is greater than or equal to 40

brilliants [131]

Answer:

Step-by-step explanation:

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3 years ago

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

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The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got: