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Elodia [21]
4 years ago
9

-2094-67 Help!!!!!!!!!

Mathematics
1 answer:
Ratling [72]4 years ago
4 0

Answer:

− 2161

Step-by-step explanation:

Subtract  67  from -2094

If you want me to show work, let me know!

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In six months, 33.6 gallons were used. Find the unit rate.
Nana76 [90]

I believe the answer is 5.6

Just divide 33.6 by 6

6 0
4 years ago
Find x. Round your answer to the nearest tenth of a degree.<br> 15<br> x<br> 10
inna [77]

Answer:

x is approximately 48.2.

Step-by-step explanation:

Use the trig function of cosine, or adjacent over hypotenuse.

cos theta = adjacent / hypotenuse

Substitute variables.

cos x = 10 / 15

Apply inverse cosine to both sides.

x = cos^-1(10/15)

Evaluate.

x ≈ 48.2

6 0
3 years ago
Read 2 more answers
Help me on this question
tatyana61 [14]

Answer:

The single transformation that maps shape A into shape B is 4 steps right and 3 steps down.

8 0
4 years ago
Please answer ASAP!! Consistently wash your hands for 1 minute.
diamong [38]

Each peach costs $0.56 and the equations used to solve that is 4x= 2.24 where x is the cost of 1 peach.

Step-by-step explanation:

Step 1:

It is given that all the peaches weigh the same and that 4 peaches weigh 1 pound.

Assume that each peach costs x.

So the cost for 4 peaches is given by 4x.

Step 2:

The cost of 1 pound of peaches is given as $2.24.

1 pound of peaches=4x.

So 4x= 2.24, x = \frac{2.24}{4}.

x = 0.56.

So each peach costs $0.56.

5 0
3 years ago
A population has a mean muequals160 and a standard deviation sigmaequals20. Find the mean and standard deviation of the sampling
hoa [83]

Answer:

Mean 160

Standard deviation 2.63

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 160, \sigma = 20

Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 58.

Mean 160

Standard deviation s = \frac{20}{\sqrt{58}} = 2.63

6 0
4 years ago
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