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bazaltina [42]
3 years ago
5

Round the factor to estimate the products

Mathematics
1 answer:
shutvik [7]3 years ago
4 0
What is the equation to round
You might be interested in
HALP ITS DUE TODAY and somehow im struggling and this is week 3 -_-​
Yuliya22 [10]

Answer:

Try to look for the pattern.

As you can see on the first column, the last three numbers line up by +3 (12 to 15 to 18). Proof - 12 + 3 = 15 + 3 = 18.

So you go back by subtracting 3. 12 - 3 = 9 - 3 = 6 - 3 = 3

For the other column, the pattern is +17. Proof -   51 - 34 = 17, 102 - 85 = 17.

So do the same thing as in the first column.

Results:

3                 17

6                 34

9                 51

12                68

15                85

18                102

5 0
3 years ago
Select the correct answer.
masha68 [24]

Answer:

Option C

Step-by-step explanation:

We want to know the percentage of women among people who only prefer exercise.

We have the following information:

                Diet Only      Exercise Only   Diet and Exercise

Men                 7                 28                           15

Women          22                   18                           10

Then we get the total of people who prefer just exercise.

28 + 18 = 46

Now the proportion of women who only prefer exercise is calculated as:

w = \frac{18}{46}\\\\w = 0.39

Therefore we must search among the options the table that shows a proportion of 39 for women who prefer only the exercise.

This table is in option C.

C.

                        Diet Only     Exercise Only         Diet and Exercise

Men                    0.24                  0.61                   0.60

Women             0.76                  0.39                   0.40

3 0
3 years ago
Suppose the expected tensile strength of type-A steel is 103 ksi and the standard deviation of tensile strength is 7 ksi. For ty
ExtremeBDS [4]

Answer:

a

i So  the approximate distribution of \= X is \mu_{\= X} =103 and  \sigma_{\= X} = 0.783

ii So the approximate distribution of \= Y is \mu_{\= Y} =105 and  \sigma_{\= Y} = 0.645

b

 the approximate distribution of  \=X  - \= Y is E (\= X - \= Y)  = -2 and  \sigma_{\= X  - \=Y}=1.029

Here we can see that the mean of the approximate distribution is negative which tell us that this negative value of the  data for  \=X  - \= Y sample   are more and their frequency occurrence is higher than the positive values  

c

the value of  P(-1 \le \=X - \= Y  \le 1) is = -0.1639    

Step-by-step explanation:

From the question we are given that

       The expected tensile strength of the type A steel is  \mu_A = 103 ksi

        The standard deviation of type A steel is  \sigma_A = 7ksi

         The expected tensile strength of the type B steel is \mu_B = 105\ ksi

            The standard deviation of type B steel is  \sigma_B = 5 \ ksi

Also the assumptions are

       Let \= X be the sample average tensile strength of a random sample of 80 type-A specimens

Here n_a =80

      Let \= Y be  the sample average tensile strength of a random sample of 60 type-B specimens.

  Here n_b = 60

Let the sampling distribution of the mean be

             \mu _ {\= X} = \mu

                   =103

 Let the sampling distribution of the standard deviation be

               \sigma _{\= X} = \frac{\sigma }{\sqrt{n_a} }

                     = \frac{7}{\sqrt{80} }

                    =0.783

So What this mean is that the approximate distribution of \= X is \mu_{\= X} =103 and  \sigma_{\= X} = 0.783

For \= Y

 The sampling distribution of the sample mean is

               \mu_{\= Y} = \mu

                    = 105

  The sampling distribution of the standard deviation is

               \sigma _{\= Y} = \frac{\sigma }{\sqrt{n_b} }

                    = \frac{5}{\sqrt{60} }

                    = 0.645

So What this mean is that the approximate distribution of \= Y is \mu_{\= Y} =105 and  \sigma_{\= Y} = 0.645                      

Now to obtain the approximate distribution for \=X  - \= Y

               E (\= X - \= Y) = E (\= X) - E(\= Y)

                                =  \mu_{\= X} - \mu_{\= Y}

                                = 103 -105

                                = -2

The standard deviation of \=X  - \= Y is

               \sigma_{\= X  - \=Y} = \sqrt{\sigma_{\= X}^2 - \sigma_{\= Y}^2}

                         = \sqrt{(0.783)^2 + (0.645)^2}

                         =1.029

Now to find the value of  P(-1 \le \=X - \= Y  \le 1)

  Let us assume that F = \= X - \= Y

    P(-1 \le F \le 1) = P [\frac{-1 -E (F)}{\sigma_F} \le Z \le  \frac{1-E(F)}{\sigma_F} ]

                             = P[\frac{-1-(-2)}{1.029}  \le  Z \le  \frac{1-(-2)}{1.029} ]

                             =  P[0.972 \le Z \le 2.95]

                             = P(Z \le 0.972) - P(Z \le 2.95)

Using the z-table to obtain their z-score

                             = 0.8345 - 0.9984

                             = -0.1639

                   

3 0
3 years ago
Which expressions are equivalent to 3(6+b)-(2b+1)
EastWind [94]

Answer:

The answer is b+17

Step-by-step explanation:

4 0
3 years ago
Please help<br><br>4(4+2x)=x(x+5)​
lapo4ka [179]

Answer:

EF = 6

Step-by-step explanation:

Using the secant- secant power theorem, that is

GF × GE = GH × GS

4(4 + 2x) = 5(5 + x) ← distribute both sides

16 + 8x = 25 + 5x ( subtract 5x from both sides )

16 + 3x = 25 ( subtract 16 from both sides )

3x = 9 ( divide both sides by 3 )

x = 3

Then

EF = 2x = 2 × 3 = 6

3 0
2 years ago
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