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ser-zykov [4K]
2 years ago
11

Fundamental Counting:

Mathematics
1 answer:
arsen [322]2 years ago
4 0
32 becuas you have to go six times four and then 4 times 2 and then add them together
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The record high temperature in January was 18 degrees. The record low temperature was –7 degrees. What is the amount of change b
vodka [1.7K]

Answer: 25^{\circ}

Step-by-step explanation:

Given

The highest temperature recorded is 18^{\circ}

The lowest temperature recorded is -7^{\circ}

The amount of change between the high and the low temperatures is

\Rightarrow 18-(-7)=18+7\\\Rightarrow 25^{\circ}

6 0
3 years ago
Find the product -4(6)
Lerok [7]

Answer:-24

Step-by-step explanation:

8 0
2 years ago
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Y = (x+3)² – 64<br> how do you write this in standard form
gregori [183]

Answer:

i think its y = x² + 6x - 55

7 0
2 years ago
Diameter=10.5 in . Determine the area of each circle. Use 3.14 or 22/7 for pie . Round to the nearest tenth.
zloy xaker [14]

Answer:

86.5 square inches

Step-by-step explanation:

Area of circle: pi*r^2

  • first find the radius

10.5in /2= 5.25in

  • find the square

5.25^2=27.5625

  • multiply with pi

27.5625*3.14=86.54625

rounded 86.5 in

5 0
2 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
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