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2 years ago

Fundamental Counting:

Mathematics

1 answer:

arsen [322]2 years ago

4 0

32 becuas you have to go six times four and then 4 times 2 and then add them together

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The record high temperature in January was 18 degrees. The record low temperature was –7 degrees. What is the amount of change b

vodka [1.7K]

Answer: $25^{\circ}$

Step-by-step explanation:

Given

The highest temperature recorded is $18^{\circ}$

The lowest temperature recorded is $-7^{\circ}$

The amount of change between the high and the low temperatures is

$\Rightarrow 18-(-7)=18+7\\\Rightarrow 25^{\circ}$

6 0

3 years ago

Find the product -4(6)

Lerok [7]

Answer:-24

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Y = (x+3)² – 64<br> how do you write this in standard form

gregori [183]

Answer:

i think its y = x² + 6x - 55

7 0

2 years ago

Diameter=10.5 in . Determine the area of each circle. Use 3.14 or 22/7 for pie . Round to the nearest tenth.

zloy xaker [14]

Answer:

86.5 square inches

Step-by-step explanation:

Area of circle: pi*r^2

first find the radius

10.5in /2= 5.25in

find the square

5.25^2=27.5625

multiply with pi

27.5625*3.14=86.54625

rounded 86.5 in

5 0

2 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago