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navik [9.2K]
3 years ago
11

Exercise questions

Mathematics
1 answer:
balu736 [363]3 years ago
3 0

Answer:

2.

a)1

b)1

c)1

Step-by-step explanation:

There's some identity trigonometric equation, which are valid for all angles,and they doesn't depends on the measure of angle!

some of em are follows:. (x is the given angle)

  • sin(x)^2+cos(x)^2=1
  • cosec(x)^2=1+cot(x)^2
  • sec(x)^2=1+tan(x)^2

You can remember these identity, its gonna help alot.

now back to question,. {x is representing angles)

for (a) sin(x)^2+cos(x)^2=1, this is true for all x, dat means that for all the angle given in question(for ,15°,30°,45°,60° and 120°),we will get 1

for(b) ,

cosec(x)^2=1+cot(x)^2

i.e, cosec(x)^2-cot(x)^2=1, again this is true for all x dat means that for all the angle given in question ,we will get 1

for (c),

sec(x)^2=1+tan(x)^2

i.e,sec(x)^2-tan(x)^2=1,again this is true for all x, dat means that for all the angle given in question ,we will get 1

✌️:)

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You have that:

 1. By definition, a binomial is a polynomial formed by two terms. 
 2. A quintic binomial is a binomial of degree 5. This means that its highest exponent is 5.
 3. Keeping this on mind, you must identify which binomial has degree 5.
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3 years ago
Describe the sample space for each of these experiments (a) A coin is tossed and a single die is rolled. (b) A paper cup is toss
kondor19780726 [428]

Answer:

a) S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) S={top,bottom,side}

c) S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

Step-by-step explanation:

The sample space is all the possible outcomes from each experiment:

a) The sample has the pairs of the result of the coin (head or tails) and the dice (a number from 1 to 6):

S={(head,1),(head,2),(head,3),(head,4),(head,5),(head,6),(tails,1),(tails,2),(tails,3),(tails,4),(tails,5),(tails,6)}

b) A paper cup can land in three different ways, on its top, bottom or  side:

S={top,bottom,side}

c) The sample space is all the cards in the deck:

S={(Ace of diamonds),(Two of diamonds),(Three of diamonds),(Four of diamonds),(Five of diamonds),(Six of diamonds),(Seven of diamonds), (Eight of diamonds),(Nine of diamonds),(Ten of diamonds), (Jack of diamonds), (Queen of diamonds), (King of diamonds), (Ace of hearts),(Two of hearts),(Three of hearts),(Four of hearts),(Five of hearts),(Six of hearts),(Seven of hearts), (Eight of hearts), (Nine of hearts),(Ten of hearts), (Jack of hearts), (Queen of hearts),(King of hearts),(Ace of clubs),(Two of clubs),(Three of clubs),(Four of clubs),(Five of clubs),(Six of clubs),(Seven of clubs), (Eight of clubs), (Nine of clubs),(Ten of clubs), (Jack of clubs),(Queen of clubs),(King of clubs),(Ace of spades),(Two of spades),(Three of spades),(Four of spades),(Five of spades),(Six of spades),(Seven of spades),(Eight of spades), (Nine of spades),(Ten of spades),(Jack of spades),(Queen of spades),(King of spades)}

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