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sertanlavr [38]
2 years ago
13

Triangle DEF, shown below, is reflected over the y-axis to form triangle D'E'F'. What are

Mathematics
1 answer:
vovikov84 [41]2 years ago
8 0

Answer:

(-6, -4).

Step-by-step explanation:

When you reflect coordinates over the y-axis, the x-coordinates remain the same, but the y-coordinates become their additive inverse.

The original coordinates for F are (6, -4).

The new coordinates for F would be F' (-6, -4).

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Find the number of elements in A 1 ∪ A 2 ∪ A 3 if there are 200 elements in A 1 , 1000 in A 2 , and 5, 000 in A 3 if (a) A 1 ⊆ A
lina2011 [118]

Answer:

a. 4600

b. 6200

c. 6193

Step-by-step explanation:

Let n(A) the number of elements in A.

Remember, the number of elements in A_1 \cup A_2 \cup A_3 satisfies

n(A_1 \cup A_2 \cup A_3)=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)

Then,

a) If A_1\subseteq A_2, n(A_1 \cap A_2)=n(A_1)=200, and if A_2\subseteq A_3, n(A_2\cap A_3)=n(A_2)=1000

Since A_1\subseteq A_2\; and \; A_2\subseteq A_3, \; then \; A_1\cap A_2 \cap A_3= A_1

So

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-200-200-1000-200=4600

b) Since the sets are pairwise disjoint

n(A_1 \cup A_2 \cup A_3)=\\n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\200+1000+5000-0-0-0-0=6200

c) Since there are two elements in common to each pair of sets and one element in all three sets, then

n(A_1 \cup A_2 \cup A_3)=\\=n(A_1)+n(A_2)+n(A_3)-n(A_1\cap A_2)-n(A_1\cap A_3)-n(A_2\cap A_3)-n(A_1\cap A_2 \cap A_3)=\\=200+1000+5000-2-2-2-1=6193

8 0
2 years ago
What is the measure of ∠K?
Ierofanga [76]
All the angles of a triangle equal 180. 101+33=144. 180-144=36. k=36
4 0
3 years ago
Graph f(x)=sin (3.14/4)x
crimeas [40]

Answer:

Step-by-step explanation:

6 0
3 years ago
Find the value of x
fgiga [73]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 35°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4x + 1 + x + 4 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:5x + 5 = 180

\qquad❖ \:  \sf \:5(x + 1) = 180

\qquad❖ \:  \sf \:x + 1 = 180 \div 5

\qquad❖ \:  \sf \:x + 1 = 36

\qquad❖ \:  \sf \:x = 36 - 1

\qquad❖ \:  \sf \:x = 35

\qquad \large \sf {Conclusion}  :

  • x = 35°
7 0
2 years ago
10 • 1/10 =1 a) This is an example of the additive inverse property
saul85 [17]

Answer:

C) Multiplicative Inverse Property

Step-by-step explanation:

Because 1/10 is the inverse of 10.

For example, 15*(1/15)=1.

5 0
3 years ago
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