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3 years ago

How to solve this using trigonometry?

Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Using SOHCAHTOA and Kenui's height and angle of depression (which is the downward angle from the horizontal ) the answer should be:

because its the Adjacent and Opposite sides use Tan;
Tan(6.8) = o/a
tan(6.8) = Distance / 219
tan(6.8)(219 = Distance
26.114 m

But because the angle of depression is the downward angle from the horizontal the answer may be Tan(83.2)(219) = 1836.589
the 83.2 coming from 90 degrees - 6.8 degrees

either way i"m still unsure because I don't see a need for the two angles or Mias involvement, sorry if I'm wrong

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Daniel has lunch at a restaurant and the cost of his meal is $49.00, because of the service, he wants to leave a 5% tip. what is

yuradex [85]

49*1.05= $51.45

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8 0

3 years ago

Solve for x: 2-3(2x-1)=-6x+5

horrorfan [7]

Answer:

x=-1

Step-by-step explanation:

1.) 2-3(2x-1)=-6x+5

2.) -1(-2x-1)=-6+5

3.) (2x+1)=-6+5

4.) (2x+1)=-1

5.) 2x=-2

6.) x=-1

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3 years ago

Ms. Cathy bought a package of pencils. Out of every 10 pencils, 5 are black. If there are 20 pencils in the pack, what fraction

Advocard [28]

Answer:

there are 10 black pensoles

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The revenue function for a production by a theatre group is R(t) = -50t^2 + 300t where t is the ticket price in dollars. The cos

Mkey [24]

Break even is the value of t where revenue=cost or R(t)=C(t)

set equal each other

-50t^2+300t=600-50t
multiply both sides by -1
50t^2-300t=50t-600
divide both sides by 50
t^2-6t=t-12
minus t-12 from both sides
t^2-7t+12=0
factor
(t-4)(t-3)=0
set each to zero
t-4=0
t=4

t-3=0
t=3
the cost is $3 or $4

it will first break even at t=3$

7 0

2 years ago

Read 2 more answers

For what values of x is log base 0.8 (x+4)>log base 0.4 (x+4)<br>Thank you!

Radda [10]

We are seeking the solution of the inequality:

$\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4)$ .

We recall that a log function $f(x)=\log_b(x)$ is either increasing or decreasing:

i) it is increasing if b>1,

ii) it is decreasing if 0<b<1.

Consider the functions $\displaystyle{ \log_{0.8}(x)$ and $\displaystyle{ \log_{0.4}(x)$ .

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)

We can check for a certain convenient point, for example x=0.8:

$\displaystyle{ \log_{0.8}(0.8)=1$ and

$\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2)$ .

Now, $\displaystyle{ \log_{0.4}(2)$ is negative since we already explained that for x>1 both functions were negative. This means that

$\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8)$ , and since $0.8\in (0, 1)$ , then this is the interval where $\displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x)$ .

So, now considering the functions $\displaystyle{ \log_{0.8}(x+4)$ and $\displaystyle{ \log_{0.4}(x+4)$ , we see that

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.

Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0

2 years ago