Question

The expression x3 – 64 can be written as (x)3 – (4)3. What is the factorization of x3 – 64?

Answer 1

Answer:

$(x-4)(x^2+4x+16)$

Step-by-step explanation:

We have $x^{3}-64=x^3-4^3$ And we know that: $a^3-b^3=(a-b)(a^2+ab+b^2)$. In our case we have that $a=x$ and $b=4$, then we can eliminate the two last options. And we have:

$x^3-4^3=(x-4)(x^2+x4+4^2)=(x-4)(x^2+4x+16)$

Then the correct factorization is the second option.

Answer 2

By factoring x^3-64 put you should get the second option as your answer

(x-4)(x^2+4x+16)