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3 years ago

I am doing Algebra for homework what is: bxbxbxb

Mathematics

1 answer:

Eduardwww [97]3 years ago

5 0

Bxbxbx = b³x³ = (bx)³

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A single standard six sides die is rolled. what is the probability the roll is a multiple of three given that it is an even numb

tankabanditka [31]

33.3%

Since we are given that it is an even number, we know there is only 3 options (2, 4, 6). Since only one of them is an even number, we know that we need the fraction 1/3 or 33.3% for a probability.

5 0

3 years ago

A system of equations is graphed on a coordinate plane.

zavuch27 [327]

Answer:

Option C is correct.

(1, 4)

Step-by-step explanation:

A system of equation is given :

2x + 3y =12 .....[1]

4x + 2y =10 .....[2]

Multiply equation [1] by 2 both sides we get;

$2(2x+3y) = 2(12)$

Using distributive property i,e $a \cdot(b+c) = a\cdot b+ a\cdot c$

4x + 6y = 24 .....[3]

Subtract equation [2] from [3] to eliminate x we get;

4x + 6y - 4x - 2y= 24 - 10

Combine like terms;

4y = 14

Divide both sides by 4 we get;

y = 3.5

Substitute the value of y in equation [1] we have;

2x + 3(3.5) =12

2x + 10.5 = 12

2x = 12 -10.5

2x = 1.5

Divide both sides by 2 we get;

x = 0.75

Solution = (0.75 , 3.5)

Best estimate solution = (1, 4)

Therefore, the best estimate solution of the given system of equation is, (1, 4)

8 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

For f(x)=3x+1 and g(x)=(x^2)-6, find (f+g)(x).

Anon25 [30]

$f(x)=3x+1;\ g(x)=x^2-6\\\\(f+g)(x)=(3x+1)+(x^266)=3x+1+x^2-6=x^2+3x+(1-6)\\\\=\boxed{x^2+3x-5}$

3 0

3 years ago

Read 2 more answers

Used Cartesian coordinate system to plot the following points

Fiesta28 [93]

(x,y)
go over x, and up or down y
if fraction then between integers (1/2)=> between 0 and 1.
0=>don't move on that axes
(0,y) move y
(x,0) move x

8 0

3 years ago