Which symbol makes the number sentence true?
2 answers:
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Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
215.20 ft^2
Step-by-step explanation:
The figure has 2 semi-circles.
First we find the area of each circle using the formula because that is the area formula for a circle.
The semi-circle to the left gives the diameter which is 22 feet. The radius would be half the diameter thus r=11 for semi-circle one.
Then we are to find the diameter of the second semi-circle. Given the entire length to be 30 feet, 30-22 leaves us with 8 feet as its diameter thus r=4.
Left: r=11
Right: r=4
Then, plugging both into the formula for area of a circle, we get
Left: 380.1327
Right: 50.26548
We must divide each by two because we are only looking for semi-circle which is exactly half the area of a full circle.
Then,
Left: 190.066
Right: 25.1327
190.066+ 25.1327= 215.199 = 215.2ft^2