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marishachu [46]
3 years ago
11

Which of the following describes the zeroes of the graph of f(x) = –x^5 + 9x^4 – 18x^3?

Mathematics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

second option

Step-by-step explanation:

Given

f(x) = - x^{5} + 9x^{4} - 18x³

To find the zeros let f(x) = 0, that is

- x^{5} + 9x^{4} - 18x³ = 0 ( multiply through by - 1 )

x^{5} - 9x^{4} + 18x³ = 0 ← factor out x³ from each term

x³ (x² - 9x + 18) = 0 ← in standard form

x³(x - 3)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x³ = 0 ⇒ x = 0 with multiplicity 3

x - 3 = 0 ⇒ x = 3 with multiplicity 1

x - 6 = 0 ⇒ x = 6 with multiplicity 1

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Using the distributive property to find the product (y – 4)(y2 + 4y + 16) results in a polynomial of the form y3 + 4y2 + ay – 4y
Crank

Answer:

The answer to your question is a = 16

Step-by-step explanation:

Polynomial

                  (y - 4) (y² + 4y + 16)

Process

1.- Multiply y by each term of the polynomial

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2.- Multiply -4 by each term of the polynomial

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3.- Write both results

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