Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer:
64
Step-by-step explanation:
Answer:
87: y = 5
88: y = 0
89: y = -2
90: y = -1/2x + 9
91: y = 2x - 16
92: y = x - 11
Step-by-step explanation:
To find the slope(m): (y1 - y2)/(x1 - x2)
To find the y-intercept:
y = mx + b
Replace m with the slope and x and y with one of the sets of coordinates. Then simplify to get the y-intercept. Use the equation y = mx + b and replace m with the slope and b with the y-intercept to get the equation.
(Sorry if this is a little confusing.)
