Which of the following describes the zeroes of the graph of f(x) = –x^5 + 9x^4 – 18x^3?
1 answer:
Answer:
second option
Step-by-step explanation:
Given
f(x) = - + 9
- 18x³
To find the zeros let f(x) = 0, that is
- + 9
- 18x³ = 0 ( multiply through by - 1 )
- 9
+ 18x³ = 0 ← factor out x³ from each term
x³ (x² - 9x + 18) = 0 ← in standard form
x³(x - 3)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x³ = 0 ⇒ x = 0 with multiplicity 3
x - 3 = 0 ⇒ x = 3 with multiplicity 1
x - 6 = 0 ⇒ x = 6 with multiplicity 1
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The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
<h3>How to find a sector area, and arc length?</h3>For a sector that has a central angle of θ, and a radius of r;
The sector area, and the arc length are:
--- sector area
---- arc length
Here, the given parameters are:
Central angle, θ = 160
Radius, r = 5 inches
The sector area is
So, we have:
Evaluate
A = 34.92
The arc length is:
So, we have:
L = 13.97
Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively
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