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ivann1987 [24]
3 years ago
15

Given below is the odd-number function. Which of the following are equal to O(8)? 

Mathematics
2 answers:
dezoksy [38]3 years ago
4 0
The answer would be B.
For these, you plug in 8 where there ia a variable. 2(8)-1=15
Jlenok [28]3 years ago
3 0
Here, O(8) = 2(8) - 1 = 16-1 = 15
Also, O(7) + 2 = 2(7) -1 + 2 = 14+1 = 15

In short, Your Answer would be Option B and D

Hope this helps!
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-2(3x-4)=4(5x-11) Solve for x
sveta [45]

-2(3x-4)=4(5x-11)

-6x+8=20x-44

8+44=26x

26x=52

x=52/26

your answer will be x=2

6 0
3 years ago
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The elevator in the empire state building goes up to the 103rd floor and descends to -5 for parking. What does 0 represent in th
Inessa05 [86]
0 could possibly represent ground level in this situation.
5 0
3 years ago
Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0
2 years ago
How can you check to see if two fractions are equivalent please explain
Wewaii [24]

Answer:

cross multiply and they should equal the same

Step-by-step explanation:

4 0
3 years ago
James bought a cake that weighs 3 and 1 over 4 pounds. How many ounces does the cake weigh? Show your work. (5 points)
kolezko [41]

The weight of James cake in ounces is 52 ounces and the Pint of water dispensed in 20 seconds is 24 pints

<h3>Weight</h3>

  • Weight of cake = 3 1/4 pounds

1 pound = 16 ounces

Number of ounces the cake weigh = 3 1/4 pounds × 16 ounces

= 13/4 × 16

= (208) / 4

= 52 ounces

  • Water dispensed per second = 0.15 gallons
  • Number of seconds = 20 seconds

1 gallon = 4 quarts

0.15 gallon = 0.6 quarts

1 quart = 2 pints

0.6 quart = 1.2 pints

Pint of water dispensed in 20 seconds = 1.2 × 20

= 24 pints of water

Learn more about weight:

brainly.com/question/229459

#SPJ1

8 0
2 years ago
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