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Arte-miy333 [17]
3 years ago
11

Jahlil made 14 pints of icecream. she gave 1 quart to his neighbor and then made milkshakes with half the remaining ice cream. h

ow many quarts did jahlil use to make milkshakes
Mathematics
1 answer:
zzz [600]3 years ago
5 0

Answer:

She used 3 quarts to make milkshakes.

Step-by-step explanation:

Jahlil made 14 pints of ice cream.

She gave 1 quart to her neighbor .

as we know 1 quart = 2 pints

so we subtract 2 pints from 14 pints.

remaining icecream = 14 - 2 = 12 pints

Then she made milkshakes with half the remaining ice cream

half of 12 pints = 12 / 2 = 6 pints or 3 quarts

Therefore, She made milkshakes with 3 quarts.

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Answer:

The area shaded is above the line, thus y is greater than the given expression. The line is also dotted; hence y is greater than the expression, and not equal to it.

Step-by-step explanation:

7 0
3 years ago
Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified, exact value in terms o
Digiron [165]

Check the picture below.

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notice that for the perimeter we didn't include the segment BC, because the perimeter of a figure is simply the outer borders.

7 0
3 years ago
The tape diagram below represents 100\%100%100, percent.
elena-s [515]

Answer:

75 %

Step-by-step explanation:

100/4=25

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6 0
3 years ago
Hey can you help me answer this question by giving me the answer?
Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

#SPJ1

7 0
2 years ago
Adam wishes to advertise his business, so he gives packs of 16 red flyers to each restaurant
AVprozaik [17]

Answer:

16

Step-by-step explanation:

The Lcm of 16 and 4 is 16. I hope this helps

8 0
3 years ago
Read 2 more answers
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