1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Advocard [28]
3 years ago
12

The area of shaded region.

Mathematics
2 answers:
REY [17]3 years ago
8 0

Answer:

160π cm^2

Step-by-step explanation:

Looks like the radius of the shaded area is (10 cm + 3 cm), or 13 cm, and that the radius of the white region is 3 m.

Thus, the area of the shaded region is:

π(169 - 9) cm^2, or 160π cm^2.

Korvikt [17]3 years ago
5 0

Answer:

160π cm²

Step-by-step explanation:

The area of the shaded region is

area of outer circle - area of inner circle

A = πr₁² - πr₂²

r₁ is the radius of the outer circle = 10 + 3 = 13 cm

r₂ is the radius of the inner circle = 3 cm

A = π × 13² - π × 3²

  = π(169 - 9) = 160π cm² ≈ 502.65 cm² ( to 2 dec. places )

You might be interested in
It took a fish 0.6 second to reach to 1.5 feet below sea level from the surface. How many feet per second did the fish descend d
Trava [24]

Answer:

2.5 ft/sec

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A soccer player drank 3 liters of water during a game. How many milliliters did the soccer player drink?
Lapatulllka [165]

Answer:

3000 mL

Step-by-step explanation:

recall 1 liter = 1000 mL

hence

3 liters = 1000 mL x 3 = 3000 mL

8 0
3 years ago
Read 2 more answers
The solution to 2x-2+5=13 is
vodomira [7]

Answer:

x = 5

Step-by-step explanation:

Given

2x - 2 + 5 = 13, that is

2x + 3 = 13 ( subtract 3 from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

4 0
4 years ago
Please help, this is my review, and I have a test tomorrow. But based on what I did, none of my answers matched the ones below.
lukranit [14]

Answer:

  a)  21, 34.5, 54.75, 85.125

Step-by-step explanation:

All of the answer choices differ in the first term, so that is the only one you need to figure here. However, we will do them all, so you can see it done.

We note that x > 0 for all of the values of x that we need to use. That means the recursive relation is the one we're using for computation.

f(1) = 3/2·f(0) +3 = (3/2)(12) + 3 = 18 +3 = 21 . . . . . . matches choice (a)

f(2) = 3/2·f(1) +3 = (3/2)(21) +3 = 63/2 +3 = 69/2 = 34.5

f(3) = 3/2·f(2) +3 = (3/2)(34.5) +3 = 51.75 +3 = 54.75

f(4) = 3/2·f(3) +3 = (3/2)(54.75) +3 = 82.125 +3 = 85.125

__

When you're computing for sequential input values, each depends on the previous value you computed.

_____

<em>Additional comment</em>

Using an exponential regression calculator (or spreadsheet), the explicit function can be found to be ...

  f(x) = 18·1.5^x -6

6 0
2 years ago
Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.
dezoksy [38]

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A <em>parallel</em> to vector B is defined by this formula:

\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b (1)

Where \|\vec b\| is the norm of vector B.

And the projection of vector A <em>perpendicular</em> to vector B is:

\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b} (2)

If we know that a = \langle -5, -1, 1 \rangle and \vec b = \langle -6, 0, 6 \rangle, then the projections are now calculated:

\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle

\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle

\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0
3 years ago
Other questions:
  • Two friends start a business. Together they spent 800 dollars for their initial inventory. They will sell all of their initial i
    9·1 answer
  • Which is an example of an operation? <br> A. Y<br> B. 6ab<br> C. +<br> D. 12
    9·2 answers
  • I want to take a survey of students currently enrolled in my statistics course. There are 250 of them, so I number them from 001
    15·1 answer
  • The mass of a small virus is 10^-20 kg. The mass of an average human cell is 10^-12 kg. Which of the two has lesser mass? how ma
    10·2 answers
  • An airplane travels 226 miles in two hours at that rate how far will the airplane travel in eight hours
    5·2 answers
  • 3(4x + 5) = 12 Which of the following correctly shows the beginning steps to solve this equation?
    11·1 answer
  • Find the difference between (7,-1) and (-8,-9)
    9·2 answers
  • PLEASE HELP!! URGENT!!!
    8·1 answer
  • PLEASE HELP!! will be marked brainliest!!
    13·2 answers
  • How many times will the graph of this equation cross the x-<br> axis?<br> y= 22^2– 7x - 9
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!