Rob wants to draw a sector with half the arc length of the sector shown. Which method will work?
1 answer:
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g(1)=-1 : We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1)=-1 is false.
g(0)=0 : We need to check values of function for x=0. From the graph, we can see, for x=0 the value of y is 0.
So, g(0) =0 is true.
g(4)=-2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to -2.
So, g(4)=-2 is false.
g(1)=1 :We need to check values of function for x=1. From the graph, we can see, for x=1 the value of y is 1.
So, g(1) =1 is true.
g(-1)=1 :We need to check values of function for x=-1. From the graph, we can see, for x=-1 the value of y is 1.
So, g(-1)=1 is true.
g(4)=2 :We need to check values of function for x=4. From the graph, we can see, for x=4 the value of y is going up but it's not equal to 2.
So, g(4)=2 is false.
Hello there.
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
+ 
=
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span> + = 
.
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>
<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
</span><span>
Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span>
<span>Tyrone has 8/12 quarts of paint.
Hope This Helps You!
Good Luck Studying ^-^</span>