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Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:8^4 + 14^36 is the perimeter because they are for sides in a rectangle so you have to double the amount.
Answer:
Ur answer is #1 = A number line from negative 10 to 10 is shown with numbers labeled at intervals of 2. An arrow is shown from point 0 to negative 2. Another arrow points from negative 2 to 8.
Step-by-step explanation:
The arrow from 0 to -2 represents the initial "-2" of the problem. <em>Adding </em>-10 would put an arrow of length 10 from that point to the left to -12. However, you are <em>subtracting </em>-10, so that arrow is reversed and goes from -2 to +8.
