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Alina [70]
3 years ago
15

What is the value of the expression 1 – r – a when r = 20 and a = 6?

Mathematics
2 answers:
Studentka2010 [4]3 years ago
6 0
B. -25, because 1 minus 20 is -19, then you subtract 6 from -19, then the answer is -25.
rodikova [14]3 years ago
4 0
1 - r - a      r=20    a =6
1 - 20 - 6 
  -19 - 6 =  -19 + (-6) 
     -25 would be the answer 


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The cast of the play makes 275 programs for 5 shows. How many programs will be needed for 13 shows?
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Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin
Artemon [7]
"<span>Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find \bar{d}, s_{d}, the t-test statistic, and the critical values to test the claim that \mu_{d} = 0"

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find </span><span>\bar{d}
You are asked to find the mean difference between the two variables, which is given by the formula:
\bar{d} =  \frac{\sum (x - y)}{n}

These are the steps to follow:
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In our example: 
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B) Find <span>s_{d}
</span><span>You are asked to find the standard deviation, which is given by the formula:
</span>s_{d} =  \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }

These are the steps to follow:
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In our example:
s_{d} = \sqrt{ \frac{101.5}{8-1} }
= √14.5
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C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
t =  \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}

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SE =  \frac{ s_{d} }{ \sqrt{n} }

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract  \mu_{d}
6) divide by the standard error

In our example:
SE = 3.81 / √8
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The problem gives us <span>\mu_{d} = 0, therefore:
t = [(9.75 - 9) - 0] / 1.346</span>
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D) Find t_{\alpha / 2}
You are asked to find what is the t-value for a 0.05 significance level.

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<h3><u>Answer:</u></h3>

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<h2><u>Step-by-step explanation:</u></h2>

<u>Finding the Common Ratio:</u>

We know that the formula for the common ratio of a GP is:

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<em>replacing the values, taking n=2</em>

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