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jarptica [38.1K]
3 years ago
14

a number when on the to the nearest 10 is equal to 50 the same number one on the to the nearest hundred is 100​

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

50 - 54

Step-by-step explanation:

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A. 5/18<br><br> B. 4/9 <br><br> C. 1/2<br><br> D. 5/9
schepotkina [342]

|\Omega|=9\cdot8=72\\ |A \cap B|=5\cdot4=20\\\\ P(A \cap B)=\dfrac{20}{72}=\dfrac{5}{18}\Rightarrow \text{A}

5 0
3 years ago
On Friday there were 8 snowboarders for every 3 skiers at Slovak ski resort. On Saturday the ratio of the number of snowboarders
atroni [7]

Answer:

There are 46 more skiers than snowboarder

Step-by-step explanation:

Given

Ratio of Snowboarders to Skiers

On Friday:

Ratio = 8 : 3

On Saturday:

Ratio = 4 : 7

Population = 168

Required

Determine the difference in the number of skiers and snowboarders on Saturday

On Saturday, we have

Ratio = 4 : 7

Calculate Total

Total = 4 + 7

Total = 11

Calculate the number of skiers

Skiers = \frac{7}{11} * 168

Skiers = \frac{1176}{11}

Skiers = 107 (Approximated)

Calculate the number of snowboarders

Snowboarders = \frac{4}{11} * 168

Snowboarders = \frac{672}{11}

Snowboarders = 61 (Approximated)

Calculate the difference

Difference = 107 - 61

Difference = 46

<em>Hence, there are 46 more skiers than snowboarder</em>

6 0
3 years ago
Irina predicted that she would sell 75 books, but she actually sold 95 books. Which expression would find the percent error?
dolphi86 [110]

Answer:

d

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Question 1
Tpy6a [65]

Answer:

C is the correct answer

7 0
3 years ago
Read 2 more answers
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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