<span><span> STEP 1. </span><span><span>x/5+6= 36
STEP 2. x/5 = 30
STEP TRES x= 150</span> </span></span>
Complete question :
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year
how many after one year
how many after two years
Answer:
39 deers
51 deers
Step-by-step explanation:
The question can be expressed using the compounding rate formula:
A = P(1+r)^t
A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time
After 1 year, t = 1
A = 30(1 + 0.3)^1
A = 30(1.3)^1
A = 39 deers
B.)
After 1 year, t = 2
A = 30(1 + 0.3)^2
A = 30(1.3)^2
A = 50.7
A = 51 deers approximately
Do you mean D for the last choice?
The answer is D, if that is what you meant.
The 1/4 must be positive since the 1/2 is positive in the equation and the second numbers are all positive in the choices.
Also, 1/4 of 2 is 1/2, so D has to be the answer.
I hope this helps.
