All categories

3 years ago

Use the graph of the function to find the domain of f. (Enter your answer using interval notation.).

Mathematics

1 answer:

Ulleksa [173]3 years ago

6 0

Answer:

Domain: (-∞,0) ∪ [0,∞)

Range: [-3,∞)

f(0) = -3

You might be interested in

What is equal to 6(x-4)

nadezda [96]

Answer:

6x - 24

Step-by-step explanation:

6(x-4) .....

Multiply the parentheses by 6:

6x - 6 x 4

Multiply the numbers:

6x - 24

5 0

4 years ago

All the numbers round to 7 except 6.61 7.89 6.58 7.37

alisha [4.7K]

7.89 rounds off to 8

6 0

2 years ago

Read 2 more answers

What is the area of the sector ?

worty [1.4K]

They forget to say "not to scale". I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first. By the Law of Cosines

$x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ$

We have an isosceles triangle formed by two radii of 9 cm and x=PQ. By the Law of Cosines again,

$x^2 = 9^2 + 9^2 - 2(9)(9) \cos B$

$x^2 = 162 - 162 \cos B$

$\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}$

$\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}$

$B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)$

The area of the circle is the fraction given by the angle,

$A = \dfrac{B}{360^\circ} \pi r ^2$

$A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2$

$A\approx 24.7474332960707$

Answer: 24.7 sq cm

8 0

3 years ago

The length and width of a rectangle are in a 7:2 ratio. Find the width of the perimeter is 72.

scoray [572]

length = 7x
width = 2x

2(7x + 2x) = 72
7x + 2x = 72/2
9x = 36
x = 36/9
x = 4

width = 2x = 2 * 4 = 8 units

7 0

3 years ago

#3 need help with this math problem please.

kupik [55]

Answer:

undefined

Step-by-step explanation:

f(x) = 2/ (-5x-10)

Let x = -2

f(-2) = 2/ (-5(-2)-10)

=2/(10-10)

=2/0

= undefined

5 0

3 years ago