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3 years ago

Line segments AB and CD are

Mathematics

1 answer:

dalvyx [7]3 years ago

8 0

Answer:

x = 16 or -2

Step-by-step explanation:

If both lines are congruent, their magnitudes are equal.

To find the magnitude of a line, the equation to use is;

D = √(x2-x1)^2 + (y2-y1)^2

So for AB, we have

D = √(-2 + 11)^2 + (5 + 3)^2

D = √81 + 64 = √145

For the second line

The distance would be;

D = √x-7)^2 + (9-1)^2

D = √(x-7)^2 + 8^2

Equate both magnitude

√145 = √(x-7)^2 + 64)

Simply remove the square roots on both sides

145 = 64 + (x - 7)^2

145 -64 = (x -7)^2

81 = (x-7)^2

Thaw the square root of both sides

x - 7 = 9

or x -7 = -9

x = 9 + 7 or x = -9 + 7

x = 16 or -2

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Function f is an exponential function. It predicts the value of a famous painting, in thousands of dollars, as a function of the

nalin [4]

Answer:

$y=8 \cdot (\frac{5}{4})^x$

$f(x)=8 \cdot (\frac{5}{4})^x$

$f(x)=8 \cdot (1.25)^x$

Step-by-step explanation:

We are going to see if the exponential curve is of the form:

$y=a \cdot b^x$ , ( $b\neq 0$ ).

If you are given the $y-$ intercept, then $a$ is easy to find.

It is just the $y-$ coordinate of the $y-$ intercept is your value for $a$ .

(Why? The $y-$ intercept happens when $x=0$ . Replacing $x$ with 0 gives $y=a \cdot b^0=a \cdot 1=a$ . This says when $x=0 \text{ that} y=a$ .)

So $a=8$ .

So our function so far looks like this:

$y=8 \cdot b^x$

Now to find $b$ we need another point. We have two more points. So we will find $b$ using one of them and verify for our resulting equation works for the other.

Let's do this.

We are given $(1,10)$ is a point on our curve.

So when $x=1$ , $y=10$ .

$10=8 \cdot b^1$

$10=8 \cdot b$

Divide both sides by 8:

$\frac{10}{8}=b$

Reduce the fraction:

$\frac{5}{4}=b$

So the equation if it works out for the other point given is:

$y=8 \cdot (\frac{5}{4})^x$

Let's try it. So the last point given that we need to satisfy is $(2,12.5)$ .

This says when $x=2$ , $y=12.5$ .

Let's replace $x$ with 2 and see what we get for $y$ :

$y=8 \cdot (\frac{5}{4})^2$

$y=8 \cdot \frac{25}{16}$

$y=\frac{8}{16} \cdot 25$

$y=\frac{1}{2} \cdot 25}$

$y=\frac{25}{2}$

$y=12.5$

So we are good. We have found an equation satisfying all 3 points given.

The equation is $y=8 \cdot (\frac{5}{4})^x$ .

4 0

3 years ago

BRAINLIEST BRAINLIEST <br> please answer thank you

Anna [14]

Answer:

y + x = 7

Step-by-step explanation:

Standard form should be

y - 9 = -(x+2)

y = -x -2 +9

y + x = 7

6 0

2 years ago

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aliya0001 [1]

Answer:

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5 0

2 years ago

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SOVA2 [1]

Number four is B. 28.

7 0

3 years ago

A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long

alexdok [17]

Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
$tan \alpha = \frac{C}{D}$
Similarly we can do for large triangle containing flagpole:
$tan \alpha = \frac{A}{B}$

We see that these two equations have same left sides. This means that their right sides must also be same:
$\frac{C}{D} = \frac{A}{B}$
We can solve for A:
$CB=AD \\ A= \frac{CB}{D} \\ A= \frac{6*24}{3} \\ A=48 ft$

Height of flagpole is 48 feet.

8 0

3 years ago